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John Schmidt Member
Joined: 11 Dec 2007 Posts: 27 Location: Laurinburg, NC, USA
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Posted: Tue Dec 03, 2013 10:49 pm Post subject: Request for top and back data |
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I am trying to either verify, or debunk the idea that the stiffness of the back, represented by kback, compared to the stiffness of the top, ktop, is a useful number to know.
To wit: The John Masters formula
kback = (mass_back*(M5frequencyback)^2)/10,000,000
range of the above is recommended to be 1.2-1.4
ktop = (mass_top*(M5frequencytop)^2)/10,000,000
recommended value of the above is 0.8
stiffness ratio = kback/ktop
recommended 1.5 to 1.75
I have data for 2 good violins and 2 poor ones. Don Noon's and mine.
I would like to have 12 data points to help me decide to pursue the idea further or give up.
So, I would appreciate frequency of M5 and mass for tops and backs, along with a statement about the tone of the finished violin. ... poor, mediocre, very good, etc.
I will share the results, once I get 12 data points.
jpschmidt44[atsign]gmail.com |
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DonLeister Moderator
Joined: 29 Mar 2007 Posts: 383 Location: Richmond, VA
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Posted: Tue Dec 03, 2013 11:35 pm Post subject: |
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| Hi John, if I recorded that kind of data I would share it with you. |
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John Schmidt Member
Joined: 11 Dec 2007 Posts: 27 Location: Laurinburg, NC, USA
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Posted: Wed Dec 04, 2013 5:58 am Post subject: |
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| DonLeister wrote: | | Hi John, if I recorded that kind of data I would share it with you. |
Don,
I need the M5 plate frequencies and weights for top and back, plus an evaluation of the tone quality of the finished instrument.
Thanks for your interest. |
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John Schmidt Member
Joined: 11 Dec 2007 Posts: 27 Location: Laurinburg, NC, USA
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kjb Super Member
Joined: 06 Feb 2013 Posts: 385
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Posted: Mon Dec 30, 2013 9:55 am Post subject: |
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| thanks for sharing john |
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John Schmidt Member
Joined: 11 Dec 2007 Posts: 27 Location: Laurinburg, NC, USA
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Posted: Mon Dec 30, 2013 1:22 pm Post subject: |
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| kjb wrote: | | thanks for sharing john |
kjb,
You are quite welcome. More data please.
Or your thoughts about this. |
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williamwalsman Junior Member
Joined: 26 Sep 2012 Posts: 14 Location: cape cod
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Posted: Tue Dec 31, 2013 12:20 am Post subject: John Schmidt plate stiffness request |
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Hi John,
I use a formula attributed to Nigel Harris of the U.K. I won't get into the details here but if you google him you should be able to get his doctoral dissertation which explains it thoroughly. My latest violin which is the most vibrant and open sounding violin to date has the following specs. Back plate is 112 grams pre varnish with a mode 5 of 355 hz. Mode 2 is 177 +/- 5hz. This gives it a stiffness factor (Harris method) of 1.09. The top plate is 65 grams pre varnish with a mode 5 of 357hz and mode 2 of 178hz. Once again the Harris stiffness factor for top is 1.09. I don't think this formula or any other is the holy grail but I've got good results following it.
The masters of century's past probably judged proper stiffness by bending the plates in several places and listening carefully for recognizable tap tones. Not having a feel for proper stiffness obtained over decades of experience I use Dr. Harris' method to get good results. I do try to stay consistent when selecting the Spruce for the top. Very straight grain within a certain number of grain lines per inch. Why not keep as many variables consistent as possible especially when in relates to the pliable/ vibrant top plate. |
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John Schmidt Member
Joined: 11 Dec 2007 Posts: 27 Location: Laurinburg, NC, USA
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Posted: Tue Dec 31, 2013 5:52 am Post subject: Re: John Schmidt plate stiffness request |
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William,
Thanks for the data. I have added it to the graph. The new equation for the line of best fit is kback = 0.77*ktop + 0.72
The graph is found here: http://jpschmidtviolins.com/images/violin_stiffness_good_vs_poor2.jpg
At some point I will have to separate "good" into excellent and good.
Yes, I know about Harris. In fact, that is what got me started on this path. Currently I am using the equation by John Masters
kback = massback * (M5^2)/10,000,000
ktop = masstop * (M5^2)/10,000,000
Although I have not tried a Harris violin, the PRELIMINARY guess, from the graph, would be that Harris violins, in general, are not soloist violins. But that is only a guess. I would love to have data from Harris. At this point, I only have his "average" violin. Not a real one.
My violin #16 is the best one yet. I followed Masters, so naturally, I am converted, until my next "best" violin.
Do you have any data for "bad" violins? That would be useful. |
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williamwalsman Junior Member
Joined: 26 Sep 2012 Posts: 14 Location: cape cod
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Posted: Tue Dec 31, 2013 10:54 am Post subject: Masters stiffness ratio |
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John,
I'll give you two more sets of numbers.
For an early violin (in state of disrepair) with unremarkable tone, mass of back=131g. with a mode 5= 330hz. mass of front = 69g. with a mode 5 = 319. Using Masters formula I get a k(back) of 1.43 and a k(top) of .702. Ratio = 2.02 if my figuring is correct.
For a later violin with a very desirable tone though not as open and vibrant as my latest, numbers are as follows: mass(back) = 124g with a mode 5 = 346hz. mass(top) = 71g with a mode 5 = 346hz. Using the formula I get k(back)= 1.48, k(top) = .85. K ratio = 1.74
Hope this helps. Bill |
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Ken Pollard Member
Joined: 11 Apr 2007 Posts: 79 Location: Nampa, Idaho
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Posted: Tue Dec 31, 2013 2:36 pm Post subject: |
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Hi John,
Thanks for posting the graphs.
I don't understand much about the stiffness ratios, but I have some understanding of lines. Is your line fit for all the data, or just the 'good' violins?
Your graphs show two 'poor' violins that seem to lie on the line extended to the right, assuming you are not restricting the domain (the horizontal axis). Any comments on that?
I haven't measured any of this data for any of my few instruments, but I assume they would be all over the graph, as with the rest of the red diamonds!
Thanks,
Ken |
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John Schmidt Member
Joined: 11 Dec 2007 Posts: 27 Location: Laurinburg, NC, USA
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Posted: Tue Dec 31, 2013 2:51 pm Post subject: |
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| Ken Pollard wrote: | Hi John,
Thanks for posting the graphs.
I don't understand much about the stiffness ratios, but I have some understanding of lines. Is your line fit for all the data, or just the 'good' violins?
Your graphs show two 'poor' violins that seem to lie on the line extended to the right, assuming you are not restricting the domain (the horizontal axis). Any comments on that?
I haven't measured any of this data for any of my few instruments, but I assume they would be all over the graph, as with the rest of the red diamonds!
Thanks,
Ken |
Ken,
The line is for the good violins. Yes, if you continue the line to the right, it would run into a "poor" violin data point. So I am hoping there is a line segment that works. More data will tell the tale.
John |
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williamwalsman Junior Member
Joined: 26 Sep 2012 Posts: 14 Location: cape cod
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Posted: Thu Jan 02, 2014 12:53 am Post subject: more on plate stiffness figure |
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Hi John,
As I'm sure you are aware you can reach desired plate stiffness numbers for both top and back a couple different ways, reaching good relationship numbers top to back regardless of the approach. And I wonder if one way might be preferable than the other? The target numbers can be reached either by having somewhat heavier plates with lower mode 5 frequencies or slightly higher frequencies and relatively lighter plates. Or the numbers for the back reached one way and the top the opposite.
For my latest two violins, both back plates are about 12 grams +/- lighter and top plates about 7grams +/- lighter than previous violins. Yet each plate has significantly higher mode 5 hz numbers than the corresponding plates on previous fiddles. Of course one could attribute that to varying wood densities one violin to the next. But I'm very careful selecting wood, trying to maintain reasonable material consistency one instrument to the next.
But what I have changed slightly is the arching. Not the long arch or its overall height but rather somewhat pulling in the horizontal arching toward the center line of the violin at the "c" bouts.
We know that the mode 5 frequency predominantly represents the vibration running down the length of the violin. By slightly pulling in the arching at the "c" bouts it stands to reason that that might make each plate longitude-ally stiffer and thus providing higher hz numbers in spite of the reduced mass.
So that brings me back to my original question. If we are shooting for certain ratio stiffness numbers and can get there a number of different ways (higher m. lower mode 5 hz.; lower m. higher hz, perhaps going one way for the back plate and the opposite for the top, any idea which combination might be preferable? Thanks Bill |
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John Schmidt Member
Joined: 11 Dec 2007 Posts: 27 Location: Laurinburg, NC, USA
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Posted: Thu Jan 02, 2014 6:37 am Post subject: Re: more on plate stiffness figure |
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William,
Thanks for you thoughts. I have a new plot. Your data is included. One of your data points near 0.85 , 1.48, which is a green dot, because you thought it was a good violin, is right next to a red dot, which someone else labeled a "bad" violin.
So, either both of you are correct in your tone assessment, which makes the hypothesis invalid (that the relationship between top and back plate stiffness need to be within certain limits), or one, or both of you is incorrect in your tone assessment.
I would ask that you re-consider your tone evaluation for that point. I don't mean delete it. I mean just think a little more about your definition of what a good violin is. The point right next to it was labeled poor by a very experienced violin maker. So if you are correct, it will really tell a lot.
The new graph is found at http://jpschmidtviolins.com/images/violin_stiffness_good_vs_poor3.jpg
You can email me privately with your result, if you wish.
And the data from your latest violins with the different arching would be very significant as well.
Thanks a lot.
John
Last edited by John Schmidt on Fri Jan 03, 2014 9:35 pm; edited 1 time in total |
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John Masters Junior Member
Joined: 13 Mar 2013 Posts: 23
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Posted: Fri Jan 03, 2014 8:52 pm Post subject: Re: Request for top and back data |
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| John Schmidt wrote: | I am trying to either verify, or debunk the idea that the stiffness of the back, represented by kback, compared to the stiffness of the top, ktop, is a useful number to know.
To wit: The John Masters formula
kback = (mass_back*(M5frequencyback)^2)/10,000,000
range of the above is recommended to be 1.2-1.4
ktop = (mass_top*(M5frequencytop)^2)/10,000,000
recommended value of the above is 0.8
stiffness ratio = kback/ktop
recommended 1.5 to 1.75
I have data for 2 good violins and 2 poor ones. Don Noon's and mine.
I would like to have 12 data points to help me decide to pursue the idea further or give up.
So, I would appreciate frequency of M5 and mass for tops and backs, along with a statement about the tone of the finished violin. ... poor, mediocre, very good, etc.
I will share the results, once I get 12 data points.
jpschmidt44[atsign]gmail.com |
I think you should try to compare the two formulas (setting mode 2 to zero.) Then you can see a ratio which is a constant. There is a 2*pi involved with them and maybe some other constant.
If you had this ratio, you could convert from one to the other and see how much contribution comes from mode 2. Also, I wonder if your coincidence of the ratios of top and back are a coincidence. Or a mistake. 1.09 with my formula (ignoring mode 2) is a little low.
I have never looked at a comparison of top and back this way. I use the back formula to see if the back has been made too weak. I would rather make the back stiffer than less stiff. And I am contemplating putting most of the heavier graduations across the middle.
Would you tell me also what is the Harris formula exactly? You can just call the square root thingy "sqrt" as I know what it is already. |
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John Schmidt Member
Joined: 11 Dec 2007 Posts: 27 Location: Laurinburg, NC, USA
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Posted: Fri Jan 03, 2014 9:31 pm Post subject: Re: Request for top and back data |
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| John Masters wrote: |
Would you tell me also what is the Harris formula exactly? You can just call the square root thingy "sqrt" as I know what it is already. |
John M.
The Harris formula is, apparently, mass*((m5 +m2)/2)^2,
But I am not using that formula in my scatter plots. I am using yours.
His paper is found here. http://www.violin.uk.com/research/1.%20On%20graduating%20the%20thickness%20of%20violin%20plates.%20VSA.pdf
But I am sure you know that. Do you have data for one "good" and one "bad" violin? I have used your average 0.8 and 1.3 for one of the data points.
You said 1.09 is low. I don't know what you are referring to. Would you please clarify?
Thanks |
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